logpow.htm Logarithms and Complex Powers
Logarithms and Powers


arguments and Arguments
If z ≠ 0, z has the polar coordinate representation
z
= r e,
r
= |z| > 0,
θ
= arg(z).
The angle θ = arg(z) is determined only modulo 2π.
If for every z ≠ 0 we make a particular choice Arg(z), then Arg(z) is called a Principle Argument function. For such a Principal Argument function, Arg(z) is continuous at z = z0 iff for all z near z0,
|Arg(z) − Arg(z0)| < π.
Common choices for Arg(z) are
Arg(z)
= Arg[0,2π)(z)
=arg(z), 0 ≤ arg(z) < 2 π,
Arg(z)
= Arg(−π,pi](z)
= arg(z), −π < arg(z) ≤ π.
The first choice gives a Principal Argument Function which is continuous everywhere except along the positive x-axis . The second choice gives a Principal Argument Function which is continuous everywhere except along the negative x-axis .


logarithms and Logarithms

Definition. If z is a nonzero complex number then a logarithm of z is any complex number w such that
exp(w) = z.
Any logarithm is of the form
log(z)
= ln|z| + i arg(z).
If Arg(z) is a Principal Argument Function, the function
Log(z) = ln|z|+ i Arg(z)
is called a Principal Branch of the Logarithm.


Exercise. Choose
Arg(z) = Arg(−π, π](z) = arg(z), − π < arg(z) ≤ π.
Show that
Log(z) ≡ ln|z| + i Arg(z)
is analytic except along the negative x-axis .
Hint: For ℜz > 0, draw a picture to show that Arg(x + i y) = arctan([y/x]) and verify the Cauchy-Riemann equations. Then give similar representations for Arg(z) in the regions ℑz > 0 and ℑz < 0.


powers and Powers
If z ≠ 0 and a is any complex number , za is any complex number of the form
za
= ea log(z)
= ea ·(ln|z| + i arg(z)).
In general za has more than one possible value. Choosing a Principle Argument Function Arg(z) give a Principal Branch of the Power Function, which is analytic at the places where the corresponding Principal Branch Logarithm Function Log(z) is analytic (and perhaps elsewhere in special cases). The corresponding function za ≡ ea Log(z) is called a branch of the power function za.

Note that at any point where Arg(z) is continuous, Log(z) and the Branch f(z) ≡ ea Log(z) of the power function za are analytic, and
dza

dz
=a za−1    (same branches).

Exercises
1.
Show that ii is real and find the values of all of its branches.

2.
For z ≠ 0, how many values are there for z[1/2]?

3.
Show that for any branch, limz → 0 z[1/2] = 0.

If f(z) = e[1/2]Log(z), is continuous and analytic at z, then
f(z) = 1

2 f(z)
.

4.
Show that it is NOT possible to define Arg(z) in such a way that
f(z)
= z[1/2]
= e[1/2]Log(z),
= e[1/2]((ln|z| + i Arg(z)))
is analytic in the region {z| 0 < |z| < R}.

Choices of a Principal Argument Function
If D is a simply connected region not containing z=0, the function f(ζ) = [1/(ζ)] is analytic in D and for any path Cz0 → z in D from z0 to z,

z

z0 
1

ζ
  dζ ≡


Cz0 → z 
1

ζ
  dζ,
the integral being independent of the particular path chosen. Fixing z0 ∈ D and a fixed choice for Arg(z0), we can define on D:
Log(z0)
= ln|z0| + i Arg(z0),
Log(z)
= Log(z0) +
z

z0 
1

ζ
 dζ
= ln|z| + i Arg(z),
Arg(z)
= Arg(z0) +ℑ
z

z0 
1

ζ
 dζ.
A simply connected region D which does not contain z=0 can be constructed as the complement of a branch cut which consists of any simple curve Cwhich has 0 as an initial point and extends to z=∞.



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On 03 Aug 2014, 20:27.